Question

在复数范围内,分解因式x^3+2x^2+3x+6

如题，谢谢帮助

Answer 1

x^3+2x^2+3x+6
=x^2（x+2）+3(x+2)
=(x+2)(x^2+3)
=(x+2)(x+根号3i)(x-根号3i)

Answer 2

原式=(x+2)*(x^2+3)=(x+2)(x+sqrt3*i)(x-sqrt3*i)