高一数学!求详解!!速度啊
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2014-12-04 · 知道合伙人教育行家
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tanα=-1/2
(1+2sinαcosα)/(sin²α-cos²α)
= (sin²α+cos²α+2sinαcosα)/(sin²α-cos²α)
= (sinα+cosα)²/(sin²α-cos²α)
分子分母同除以cos²α:
= (tanα+1)²/(tan²α-1)
= (-1/2+1)²/{(-1/2)²-1}
= (1/4)/(-3/4)
= -1/3
(1+2sinαcosα)/(sin²α-cos²α)
= (sin²α+cos²α+2sinαcosα)/(sin²α-cos²α)
= (sinα+cosα)²/(sin²α-cos²α)
分子分母同除以cos²α:
= (tanα+1)²/(tan²α-1)
= (-1/2+1)²/{(-1/2)²-1}
= (1/4)/(-3/4)
= -1/3
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