
3个回答
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4x²-(y²-2y+1)
= 4x²-(y-1)²
=[2x-(y-1)][2x+(y-1)]
=(2x-y+1)(2x+y-1)
(x⁴+4x+4)-4y²
=(x²+2)²-4y²
=[(x²+2)-2y][(x²+2)+2y]
=(x²+2-2y)(x²+2+2y)
2. (x⁴+4x+4)-4y²
= 4x²-(y-1)²
=[2x-(y-1)][2x+(y-1)]
=(2x-y+1)(2x+y-1)
(x⁴+4x+4)-4y²
=(x²+2)²-4y²
=[(x²+2)-2y][(x²+2)+2y]
=(x²+2-2y)(x²+2+2y)
2. (x⁴+4x+4)-4y²
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