已知cos(π/6—α)=1/3.则cos(5/6π+α)· sin(2/3π-α)=?
其中一步sin(2/3π-α)=sin[3π/2-(5π/6+α)]=-cos(5/6π+α)为什么sin[3π/2-(5π/6+α)]能化成-cos(5/6π+α)...
其中一步
sin(2/3π-α)= sin[3π/2-(5π/6+α)]=-cos(5/6π+α)
为什么sin[3π/2-(5π/6+α)]能化成 -cos(5/6π+α) 展开
sin(2/3π-α)= sin[3π/2-(5π/6+α)]=-cos(5/6π+α)
为什么sin[3π/2-(5π/6+α)]能化成 -cos(5/6π+α) 展开
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