Question

几道因式分解题，做做很快的！！能追加分！！！~~~~~~~求解，，急急急~~~~~~！！！！！！！！！！！！！！

(x-1)+b^2(1-X)
(x^2+2x)^2-(2x+4)^2
(x^2+2x)^2+2(x^2+2x)+1
m^2/9-2mn/3=n^2
(x+y)^2-18(x+y)+81
4-12(x-y)+9(x-y)^2
4xy^2-4x^2y-y^3
3-6x+3x^2
-a+2a^2-a^3
a^2-2a(b+c)+(b+c)^2
a^2(2a-3)+b^2(3-2a)
(x^2+16y^2)^2-64x^2y^2
16x^5-8x^3y^2+xy^4
a^5b^5-2a^3b^3+ab
(x^2-x)-(x-1)^2

Answer 1

(x-1)+b^2(1-X)=(x-1)（1+b^2）
(x^2+2x)^2-(2x+4)^2=(x^2+2x+2x+4)（x^2+2x-2x-4）=(x+2)^2(x+2)(x-2)
(x^2+2x)^2+2(x^2+2x)+1=(x^2+2x+1)^2=(x+1)^4

m^2/9-2mn/3=n^2
(m/3-n)^2=0
m/3=n

(x+y)^2-18(x+y)+81=(x+y-9)^2

4-12(x-y)+9(x-y)^2=(3(x-y)-4)^2

4xy^2-4x^2y-y^3=-y(4x^2-4xy+y^2)=-y*(2x-y)^2

3-6x+3x^2=3(1-2x+x^2)=3(1-x)^2

-a+2a^2-a^3=-a(1-2a+a^2)=-a(1-a)^2

a^2-2a(b+c)+(b+c)^2=(a-(b+c))^2

a^2(2a-3)+b^2(3-2a)=-(2a-3)(a^2-b^2)=-(2a-3)(a-b)(a+b)

(x^2+16y^2)^2-64x^2y^2=(x^2-y^2)^2

16x^5-8x^3y^2+xy^4=x(4x^2-y^2)^2

a^5b^5-2a^3b^3+ab=ab(a^2b^2-1)^2

(x^2-x)-(x-1)^2=x(x-1)-(x-1)^2=(x-1)(x-x+1)=x-1

Answer 2

1 （X-1)(1+B)(1-B)
2 (X+2)^3(X-2)
3 (X+1)^4

Answer 3

(x-1)+b^2(1-X)
=(x-1)(1-b^2)
=(x-1)(1-b)(1+b)

Answer 4

看起来很无聊