Question

用换元法解方程2xx2-1-x2-1x-72=0时,可设y=xx2-1,那么原方...

用换元法解方程2xx2-1-x2-1x-72=0时,可设y=xx2-1,那么原方程可化为关于y的整式方程是______.

Answer 1

设y=
x
x2-1
,则原方程变形为2y-
1
y
-
7
2
=0,
方程两边乘以2y得4y2-7y-2=0.
故答案为4y2-7y-2=0.