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10.(1) ∵∠2=1/2∠ABC,∠4=1/2∠ACB∴∠BGC=180°-∠2-∠4=180°-1/2(∠ABC+∠ACB)
(2)∠BCG=180°-1/2(∠ABC+∠ACB)
=180°-∠2-∠4
=180°-1/2∠ABC-1/2∠ACB
=180°-1/2(∠ABC+∠ACB)
=180°-1/2(180°-∠A)
=90°+1/2∠A
(2)∠BCG=180°-1/2(∠ABC+∠ACB)
=180°-∠2-∠4
=180°-1/2∠ABC-1/2∠ACB
=180°-1/2(∠ABC+∠ACB)
=180°-1/2(180°-∠A)
=90°+1/2∠A
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