Question

若m等于它的倒数，则分式(m^2+4m+4/m^2-4)/(m^2+2m/m-2)

的值为?

Answer 1

m=1,-1.若m=1,则答案为2.1。若m=-1,则无解。所以答案为2.1

Answer 2

m=1/m
=>m=1,或者-1
(m^2+4m+4/m^2-4)/(m^2+2m/m-2)
=(m+2)²/(m+2)(m-2)*(m-2)/m(m+2)
=1/m
当m=1,分式=1,
当m=-1,分式=-1