Question

(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)具体怎么做

急用啊！！！！

Answer 1

整个式子乘以一个(3-1)再除以一个(3-1),结果等于(3^16-1)(3^16+1)/(3-1)=(3^32-1)/2

Answer 2

这个是连用平方差公式：只要你给前面加一个（3-1）再给他们×二分之一就可以了

Answer 3

(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)
=(1/2)(3-1)(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)
=(1/2)(3^2-1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)
=(1/2)(3^4-1)(3^4+1)(3^8+1)(3^16+1)
=(1/2)(3^8-1)(3^8+1)(3^16+1)
=(1/2)(3^16-1)(3^16+1)
=(1/2)(3^32-1)
=3^32/2-1/2

Answer 4

(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)
=(3-1)*(3+1)(3^2+1)(3^4+1)(3^8+1)(3^16+1)/(3-1)
=(3^32-1)/2
=3^32/2-1/2

Answer 5

就那么做啊