已知有序数组(a,b,c,d),现按下列方式重新写成数组(a1,b1,c1,d1)使a1=a+b,b1=a+c
已知一个有序数组(A,B,C,D),现按下列方式重新写成数组(A1,B1,C1,D1),使A1=A+B,B1=A+C,C1=C+D,D1=D+A,按照这个规律继续写出(A...
已知一个有序数组(A,B,C,D),现按下列方式重新写成数组(A1,B1,C1,D1),使
A1=A+B, B1=A+C, C1=C+D, D1=D+A, 按照这个规律继续写出(A2,B2,C2,D2)……,(An,Bn,Cn,Dn),若 1000<(An+Bn+Cn+Dn)÷(A+B+C+D)<2000, 则 n=_______.
麻烦详细一点,不要只是敷衍的几句话,最好有过程 展开
A1=A+B, B1=A+C, C1=C+D, D1=D+A, 按照这个规律继续写出(A2,B2,C2,D2)……,(An,Bn,Cn,Dn),若 1000<(An+Bn+Cn+Dn)÷(A+B+C+D)<2000, 则 n=_______.
麻烦详细一点,不要只是敷衍的几句话,最好有过程 展开
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假设A+B+C+D=M
则A1+B1+C1+D1=A+B+A+C+C+D+D+A=2M
同理,An+Bn+Cn+Dn=2^n*M
由1000<(An+Bn+Cn+Dn)÷(A+B+C+D)<2000
得1000<2^n<2000
n=10
祝你学习愉快!
则A1+B1+C1+D1=A+B+A+C+C+D+D+A=2M
同理,An+Bn+Cn+Dn=2^n*M
由1000<(An+Bn+Cn+Dn)÷(A+B+C+D)<2000
得1000<2^n<2000
n=10
祝你学习愉快!
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为什么A+B+A+C+C+D+D+A=2M?A+B+A+C+C+D+D+A=3A+B+2C+4D≠2A+2B+2C+2D
追答
是你写错了吧,B1=B+C吧
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