Question

若{an}为等差数列,Ap= q, Aq=p(p ≠q),则A(p+q)= ______

Answer 1

若{an}为等差数列,Ap= q, Aq=p(p ≠q),则A(p+q)=-(p+q)

具体证明见下面：

等差数列{an}的前n项和为Sn,Sp=q,Sq=p,p≠q,则S(p+q)=-(p+q)

证明：由题意，
q=Sp=a1+a2+...+ap=pa1+p(p-1)d/2
p=Sq=a1+a2+...+aq=qa1+q(q-1)d/2
两式相减，得到
q-p=(p-q)[a1+(p+q-1)d/2]
因为p≠q，故
a1+(p+q-1)d/2=-1
因此
S(p+q)=a1+a2+...+a(p+q)=(p+q)(a1+a(p+q))/2
=(p+q)(a1+a1+(p+q-1)d)/2
=(p+q)(a1+(p+q-1)d/2)
=(p+q)*(-1)
=-(p+q)

Answer 2

Ap= q, Aq=p(p ≠q),
可知d=1
A(p+q)= 0

Answer 3

0