Question

已知实数a，b，满足1/2|a-b|+√2b+c+（c-1/2)²=0,求a（b+c）的值

Answer 1

1/2|a-b|+根号2b+c+(c-1/2)的平方=0;
a-b=0;
2b+c=0;
c-1/2=0'
a=-1/4, b=-1/4.c=1/2
(a(b+c)=-1/4(-1/4+1/2)=-1/16

补充部分"
2x-1>=0;
-2x+1>=0;
x>=1/2;x<=1/2;so:x=1/2;

y=0;
x^y=1;
根号5+1的整数部分为3;
m=3+b=根号5+1;
m-1=根号5;
b+2=根号5;
根号（m-1）（b+2）=根号(根号5*根号5)=根号5

Answer 2

1/2|a-b|+√2b+c+（c-1/2)²=0,得：

a-b=0
2b+c=0
c-1/2=0

解得：
a=-1/4
b=-1/4
c=1/2

所以：
a(b+c)
=-1/4x(-1/4+1/2)
=-1/4x1/4
=-1/16