Question

已知f(x-3)=x^2+2x+1,求f(x)的解析式

要详细过程，拜托了！！

Answer 1

令t=x-3
x=t+3
f(t)=(t+3)^2+2(t+3)+1
=t^2+6t+9+2t+6+1
=t^2+8t+16
∴f(x)=x^2+8x+16

☆⌒_⌒☆ 希望可以帮到you~

Answer 2

令t=x-3,x=t+3
则f(t)=(t+3)^2+2(t+3)+1=t^2+8t+16
所以f(x)=x^2+8x+16

Answer 3

令t=x-3
x=t+3
f(t)=(t+3)^2+2(t+3)+1
=t^2+6t+9+2t+6+1
=t^2+8t+16
∴f(x)=x^2+8x+16