Question

2次根式计算题：根号a/b+根号b/a-根号(a/b+b/a+2)

2.已知x(根号3/x)+9(根号x/3)-根号12x=8，求x

Answer 1

根号a/b+根号b/a-根号(a/b+b/a+2)
=根号a/b+根号b/a-根号(根号a/b+根号b/a)^2
=根号a/b+根号b/a-(根号a/b+根号b/a)
=0

x(根号3/x)+9(根号x/3)-根号12x=8
x(根号3x/x)+9(根号x/3)-根号12x=8
根号3x+3根号3x-2根号3x=8
2根号3x=8
3x=16
x=16/3

Answer 2

(√a √b)/(a b 2√ab)=(√a √b)/(√a √b)^2=1/(√a √b) =(√a-√b)/(a-b) √ab/(a√b-b√a)=√ab/(√ab(√a-√b)