1个回答
展开全部
x²-3x+1=0
x²=3x-1
分式x四次方+x²+1分之x²
=x^2/(x^4+x^2+1)
=x^2/(x^2(x^2+1)+1)
=x^2/((3x-1)(3x-1+1)+1)
=x^2/(9x^2-3x+1)
=x^2/(9(3x-1)-3x+1)
=x^2/(27x-9-3x+1)
=x^2/(24x-8)
=3x-1/8(3x-1)
=1/8
x²=3x-1
分式x四次方+x²+1分之x²
=x^2/(x^4+x^2+1)
=x^2/(x^2(x^2+1)+1)
=x^2/((3x-1)(3x-1+1)+1)
=x^2/(9x^2-3x+1)
=x^2/(9(3x-1)-3x+1)
=x^2/(27x-9-3x+1)
=x^2/(24x-8)
=3x-1/8(3x-1)
=1/8
本回答由提问者推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
