Question

A,B,C,D,E,F是1到9之间得到任何数，ABCDEF*2=CDEFAB,CDEFAB*2=EFABCD,ABCDEF这六位数是什么

Answer 1

a = 1, b = 4, c = 2, d = 8, e = 5, f = 7

C代码:
# include <stdio.h>
//根据题意确定循环上下限
int max = 1000000;
int min = 1000000 / 2 / 2;

int ABCDEF;
int CDEFAB;
int EFABCD;

int main(int argc, char **argv)
{
for (ABCDEF = 100000; ABCDEF < min; ABCDEF++)
{
int A = ABCDEF / 100000;
int B = (ABCDEF % 100000) / 10000;
int C = (ABCDEF % 10000) / 1000;
int D = (ABCDEF % 1000) / 100;
int E = (ABCDEF % 100) / 10;
int F = (ABCDEF % 10);

if (C <= A || E <= C)
{
continue;
}

CDEFAB = C * 100000 + D * 10000 +
E * 1000 + F * 100 + A * 10 + B;

if (CDEFAB != ABCDEF * 2)
{
continue;
}

EFABCD = E * 100000 + F * 10000 + A * 1000 +
B * 100 + C * 10 + D;

if (EFABCD == CDEFAB * 2)
{
printf("找到:%d\n", ABCDEF);
}

}

return 0;
}

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啊!牛大哥，厉害