Question

180°－79°19′ 22°16′×5 182°36′÷4 要过程啊，求求大哥大姐了

Answer 1

180°－79°19′
=(179°+1°)－(79°+19′)
=(179°+60')－(79°+19′)
=179°-79°+60'-19′
=100°+41′
=100°41′.

22°16′×5
=(22°+16′)×5
=22°×5+16′×5
=110°+90′
=110°+60′+30′
=110°+1°+30′
=111°30'.

182°36′÷4
=(182°+36′)÷4
=182°÷4+36′÷4
=45.5°+9′
=45°+0.5°+9′
=45°+0.5*60'+9′
=45°+30′+9'
=45°39′

[182°36′÷4
=(180°+2°+36′)÷4
=(180°+2*60'+36′)÷4
=180°÷4+156′÷4
=45°+39'
=45°39′]

Answer 2

180°－79°19′
=(179°+1°)－(79°+19′)
=(179°+60')－(79°+19′)
=179°-79°+60'-19′
=100°+41′
=100°41′.
22°16′×5
=(22°+16′)×5
=22°×5+16′×5
=110°+90′
=110°+60′+30′
=110°+1°+30′
=111°30'.
182°36′÷4