Question

[a-b-c].-[b+c-a]的平方.[c-a+b]的3次方

Answer 1

[a-b-c].-[b+c-a]的平方.[c-a+b]的3次方
=(a-b-c)(a-b-c)²[-(a-b-c)³]
=-(a-b-c)^(1+2+3）
=-(a-b-c)^6

Answer 2

[a-b-c].-[b+c-a]的平方.[c-a+b]的3次方
=[-(c-a+b)][-(c-a+b)^2]*(c-a+b)^3
=(c-a+b)^6