Question

若x,y互为相反数,且(x+2)²-(y+1)²=4,求x,y的值

Answer 1

y=-x，x^2+4+4x-x^2-1+2x=4,6x=1,x=1/6,y=-1/6.
故，x=1／6，y=-1／6

Answer 2

x²+4x+4-y²-2y-1=4
∵x+y=0 x=-y
∴y²-4y+4-y²-2y-1=4
-2y=1
y=-1/6
x=1/6