求解高数全微分!!过程!!!
2个回答
2016-06-27
展开全部
Zx=[(x-y)-(x+y)]/(x+y)²=-2y/(x+y)²
Zy=[(x-y)-(x+y)(-1)]/(x+y)²=2x/(x+y)²
dz=Zxdx+Zydy=-2y/(x+y)² dx+2x/(x+y)² dy
Zy=[(x-y)-(x+y)(-1)]/(x+y)²=2x/(x+y)²
dz=Zxdx+Zydy=-2y/(x+y)² dx+2x/(x+y)² dy
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询