函数z=(x+y) ∕ (x-y)的全微分dz=
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z=u/v: u=x+y v=x-y
Z'x= Z'uU'x+Z'vV'x
=1/v-u/v^2=-2y/(x+y)^2
Z'y=Z'uU'y+Z'vV'y
=1/v+u/v^2=2x/(x+y)^2
dz=Z'xdx+Z'ydy
=-2/(x+y)^2 * [xdx-ydy]
Z'x= Z'uU'x+Z'vV'x
=1/v-u/v^2=-2y/(x+y)^2
Z'y=Z'uU'y+Z'vV'y
=1/v+u/v^2=2x/(x+y)^2
dz=Z'xdx+Z'ydy
=-2/(x+y)^2 * [xdx-ydy]
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