数学题高三
1个回答
展开全部
f(x) = √2[(1/√2)sin(x +π/3) + (1/√2)cos(x + π/3)] = √2[sin(x +π/3)cos(π/4) + cos(x + π/3)sin(π/凯芦4)]
= √2sin(x + π/空孙帆3 + π/4)
= √2sin(x + 7π/12)
T = 2π
其值域为[-√2, √斗雹2]
= √2sin(x + π/空孙帆3 + π/4)
= √2sin(x + 7π/12)
T = 2π
其值域为[-√2, √斗雹2]
本回答由提问者推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
