Question

用隐函数微分法，谢谢！

Answer 1

把y看成x的函数。y=f(x)
y^2整体就是x的复合函数。g(y)=g[f(x)]=[f(x)]^2=y^2
g'(x)
={[f(x)]^2}'
=[dg(y)/dy]*[dy/dx]
=[d(y^2)/dy]*[dy/dx]
=2y*y'
=2yy'
希望帮助你解答了本题，祝学业有成，欢迎追问。