Question

求用shell编写简单的猜数字游戏的程序，要求用case和while语句。急！

Answer 1

#!/bin/sh
while [ 1 ]
do
read -p "please enter a number between 1 to 100: " number
case $number in
    13)
        echo "you get the first prize"
    ;;
    71)
        echo "You get the second prize"
    ;;
    23)
        echo "You get the third prize"
    ;;
    *)
        echo "You lose"
    ;;
esac
done

追问

请问，程序要是先输入随便的数字，然后用case语句，最后用while语句判断该怎么编写呢？

追答

#!/bin/sh
read -p "please enter a number between 1 to 100: " number
case $number in
    13)
        prize=1
    ;;
    71)
        prize=2
    ;;
    23)
        prize=3
    ;;
    *)
        prize=4
    ;;
esac
while [ $prize -gt 0 ]
do
    if [ $prize -eq 1 ];then
        echo "You get first prize"
    elif [ $prize -eq 2 ]; then
        echo "You get second prize"
    elif [ $prize -eq 3 ]; then
        echo "You get third prize"
    else
        echo "You lose"
    fi
    break  
done

Answer 2

1-100这个范围太大，难度太高，还是在1-20范围内猜猜吧。
数字随机，玩起来更有意思。

#!/bin/sh
max=20
while true
do
read -p "Please enter a number [1-$max]: " num
let rand1="RANDOM % max + 1"
let rand2="RANDOM % max + 1"
let rand3="RANDOM % max + 1"
case $num in
$rand1)
echo "Bingo! You win First Prize."
;;
$rand2)
echo "Congratulations! You win Second Prize."
;;
$rand3)
echo "Not bad! You win Third Prize."
;;
*)
echo "Bad luck! You lose."
;;
esac
sleep2
echo
done

Answer 3

#!/bin/bash
a=`expr $RANDOM % 10`
b=0
echo "范围(0-10): "
while read -p "请给出你猜的价格: " p
do
let b++
if [ $p -eq $a ]
then
echo "恭喜你猜对了!!!"
echo "你一共猜了 $b 次"
exit 0
elif [ $p -gt $a ]
then
echo "猜高了"
else
echo "猜低了"
exit 0
fi
done