在三角形abc中 a等于根号2 b等于根号三 B等于三分之派 解三角形
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(a,b,c)=(√2,√3,(√6+√2)/2)
(A,B,C)=(π/4,π/3,5π/12)
解析:
a=√2,b=√3,C=π/3
使用正弦定理:
(1) 大边对大角
∵a<b
∴A<B=π/3
(2) a/sinA=b/sinB
√2/sinA=√3/sin(π/3)
√2/sinA=2
sinA=√2/2
A=π/4或3π/4(A=3π/4舍去)
由A=π/4,得:C=π-A-B=5π/12
c/sinC=b/sinB
c=bsinC/sinB
c=2sinC
c
=2sin(5π/12)
=2sin75°
=2sin(30°+45°)
=2(sin30°cos45°+cos30°sin45°)
=2(√2/4+√6/4)
=(√6+√2)/2
综上,
(a,b,c)=(√2,√3,(√6+√2)/2)
(A,B,C)=(π/4,π/3,5π/12)
(A,B,C)=(π/4,π/3,5π/12)
解析:
a=√2,b=√3,C=π/3
使用正弦定理:
(1) 大边对大角
∵a<b
∴A<B=π/3
(2) a/sinA=b/sinB
√2/sinA=√3/sin(π/3)
√2/sinA=2
sinA=√2/2
A=π/4或3π/4(A=3π/4舍去)
由A=π/4,得:C=π-A-B=5π/12
c/sinC=b/sinB
c=bsinC/sinB
c=2sinC
c
=2sin(5π/12)
=2sin75°
=2sin(30°+45°)
=2(sin30°cos45°+cos30°sin45°)
=2(√2/4+√6/4)
=(√6+√2)/2
综上,
(a,b,c)=(√2,√3,(√6+√2)/2)
(A,B,C)=(π/4,π/3,5π/12)
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