Question

复数题求解

求z1 z2 z3 z4

Answer 1

如图，耐心写写就行了。

Answer 2

z^4-60=0
z^4
=60
=60(cos0+isin0)
=60[cos(2kπ)+isin(2kπ)] ; k=0,1,2,3
z =60^(1/4) [cos(kπ/2)+isin(kπ/2)] ; k=0,1,2,3

追问

然后呢然后呢 我就是这样然后没算出答案

追答

k=0, z1=60^(1/4) [cos0+isin0] =60^(1/4)
k=1,z2=60^(1/4) [cos(π/2)+isin(π/2)] =60^(1/4) . i
k=2,z3=60^(1/4) [cosπ+isinπ] =-60^(1/4)
k=3,z4=60^(1/4) [cos(3π/2)+isin(3π/2) ] =-60^(1/4) .i

Answer 3

亲这里建议你用小猿搜题更快更方便