若cosα*cosβ=1,则sin(α+β)=
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cosα*cosβ=1
(cosα) = 1/cosβ
|1/cosβ| <=1
=>cosα = 1 or -1
when cosα =1, cosβ =1, sinα=0, cosβ =0
when cosα =-1, cosβ =-1, sinα=0, cosβ =0
case 1: cosα =1, cosβ =1, sinα=0, cosβ =0
sin(α+β) = sinαcosβ + cosαsinβ
=0
case 2: cosα =-1, cosβ =-1, sinα=0, cosβ =0
sin(α+β) = sinαcosβ + cosαsinβ
=0
ie
sin(α+β) =0
(cosα) = 1/cosβ
|1/cosβ| <=1
=>cosα = 1 or -1
when cosα =1, cosβ =1, sinα=0, cosβ =0
when cosα =-1, cosβ =-1, sinα=0, cosβ =0
case 1: cosα =1, cosβ =1, sinα=0, cosβ =0
sin(α+β) = sinαcosβ + cosαsinβ
=0
case 2: cosα =-1, cosβ =-1, sinα=0, cosβ =0
sin(α+β) = sinαcosβ + cosαsinβ
=0
ie
sin(α+β) =0
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