(x-y分之1+x+y分之1)除以x的平方-y的平方分之x的平方y
展开全部
解
[1/(x-y)+1/(x+y)]÷[x²y/(x²-y²)]————是这个吗？
=[1/(x-y)+1/(x+y)]×[(x-y)(x+y)/x²y]
=[(x+y)/x²y+(x-y)/x²y]
=(x+y+x-y)/x²y
=2x/x²y
=2/xy
[1/(x-y)+1/(x+y)]÷[x²y/(x²-y²)]————是这个吗？
=[1/(x-y)+1/(x+y)]×[(x-y)(x+y)/x²y]
=[(x+y)/x²y+(x-y)/x²y]
=(x+y+x-y)/x²y
=2x/x²y
=2/xy
本回答由提问者推荐
已赞过
已踩过<
评论
收起
你对这个回答的评价是？
推荐律师服务：
若未解决您的问题，请您详细描述您的问题，通过百度律临进行免费专业咨询
