Question

初二一道数学题。。。。

5a²b-{2a²b-[3a²b-ab(b-2a)÷（-1/2ab）｝

5a²b-{2a²b-[3a²b-ab(b-2a)除以（负二分之一ab）｝

Answer 1

5a²b-{2a²b-[3a²b-ab(b-2a)÷（-1/2ab）｝
=5a²b-{2a²b-[3a²b-(b-2a)÷（-1/2）｝
=5a²b-{2a²b-[3a²b+(b-2a)÷（1/2）｝
=5a²b-{2a²b-[3a²b+(b-2a)X2｝
=5a²b-{2a²b-[3a²b+2b-4a}
=5a²b-{2a²b-3a²b-2b+4a}
=5a²b-{-a²b-2b+4a}
=5a²b+a²b+2b-4a
=6a²b+2b-4a

Answer 2

=5a²b-{2a²b-[3a²b+(ab²-2a²b)2/ab]}
=5a²b-{2a²b-[3a²b+(2b-4a)]}
=5a²b-[2a²b-(3a²b+2b-4a)]
=5a²b-(2a²b-3a²b-2b+4a)
=5a²b-2a²b+3a²b+2b-4a
=6a²b+2b-4a

Answer 3

6a²b+2b-4a