Question

判断级数∑(N=1,∞) (-1)^N/(N-lnN)的收敛性,是绝对收敛还是条件收敛 如题~

Answer 1

条件收带隐敛李拆，详情蠢扰厅如图所示

Answer 2

lim(n→∞)[1/(n-lnn)]/笑指(1/n)=1
又返高lim(n→∞)[1/(n-lnn)]＝碰世配0
u(n+1)-un