Question

求函数f(x)=cos²x+2√3 sinxcosx-sin²x的周期、最大值和最小值

过程第一！谢谢！

Answer 1

f(x)
=
2ocs²x
+
2√3sinxcosx
=
cos2x
+
√3sin2x
=
2[(1/2)cos2x
+
(√3/2)sin2x]
=
2sin(2x
+
π/3)
最小正周期t
=
2π/2
=
π
最大值是:f(x)max
=
2×1
=
2