Question

已知：x²＋y²－6x＋2y＋10＝0,求x－y²的值.

Answer 1

x²＋y²－6x＋2y＋9+1＝0
(x-3)²＋(y+1)²＝0
则 x=3 y=-1

x－y²
=3-(-1)²=2

Answer 2

x²＋y²－6x＋2y＋10＝0,
x²－6x＋9+y²＋2y＋1＝0,
(x-3)^2+(y+1)^2=0
x=3,y=-1
代入，3-1=2
~~~~~~~~~~求采纳~~~~~~~~·