Question

求解, 高等数学, 这个是怎么算出来的, 怎么降幂的

Answer 1

x^3
= cos0+isin0

=cos(2kπ) + isin(2kπ)
x=[cos(2kπ) + isin(2kπ)]^(1/3)
=cos(2kπ/3) + isin(2kπ/3)

追问

厉害了！没想到还能这样降幂！