这题怎么做,函数极限
3个回答
展开全部
4x^2+3
=4x(x-1) + 4x+3
=4x(x-1) + 4(x-1) +7
lim(x->+∞) [ (4x^2+3)/(x-1) +ax+b] =0
lim(x->+∞) [ 4x+4 + 7/(x-1) +ax+b] =0
lim(x->+∞) [ (4+a)x+(4+b) + 7/(x-1) ] =0
4+a=0 and 4+b=0
a=-4 and b=-4
=4x(x-1) + 4x+3
=4x(x-1) + 4(x-1) +7
lim(x->+∞) [ (4x^2+3)/(x-1) +ax+b] =0
lim(x->+∞) [ 4x+4 + 7/(x-1) +ax+b] =0
lim(x->+∞) [ (4+a)x+(4+b) + 7/(x-1) ] =0
4+a=0 and 4+b=0
a=-4 and b=-4
已赞过
已踩过<
评论
收起
你对这个回答的评价是?
推荐律师服务:
若未解决您的问题,请您详细描述您的问题,通过百度律临进行免费专业咨询