Question

求y=根号下（sinx）+根号下（16-x2)定义域

正确答案为：[-4,-π]与[0，π]的并集。求过程

Answer 1

分别解不等式（sinx)^(1/2)=>0,(16-x^2)^(1/2)=>0，就可以得出函数x的定义域
先将（sinx)^(1/2)=>0两边平方，得sinx=>0解得；0<=x<=π
,(16-x^2)^(1/2)=>0两边平方，得16-x^2=>0解得；-4<=x<=4
{x ; -4<=x<=π }

Answer 2

sinx>o 2kπ <=x<=π +2Kπ
16-x2>0 -4<=x<=4
0<=x<=π

Answer 3

sinx>=0
0<=x<=π
16-x2>=0
-4<=x<=4
综合得
0<=x<=π