Question

如图，已知直线AB平行CD，直线EF分别交AB，CD于点E，F，EG平分∠AEF，∠1=40°，求∠2的度数?

Answer 1

∠1=∠AEG=40°
∠AEF被EG平分败高，所以睁判 ∠AEG=∠GEF=40°
∠察早尺2=180°-∠AEF=100°

Answer 2

答案为100

Answer 3

∠消纯羡1=∠AEG=40°
∠裤肆AEF被EG平分，拿拍所以 ∠AEG=∠GEF=40°
∠2=180°-∠AEF=100°赞同12| 评论(4)