Question

如图是一个滑滑梯示意图,若将滑道AC水平放置,则刚好与AB一样长..已知滑梯的高度CE =3m，CD=1m

试求滑道AC的长

Answer 1

AC=AB=AE+BE，显然CDBE是矩形，所以CD=BE=1m即AC=AE+1且CE垂直于AE，CE=3m，在直角三角形ACE中由勾股定理得CE^2+AE^2=AC^2即CE^2+AE^2=(AE+1)^2，设AE=x得3^2+x^2=(x+1)^2得x=4，AC=4+1=5m

望采纳~~~！