初中数学 相似三角形 2.3两道题 怎么做哈! 最好是写纸上的
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A={x|x=t^2+(a+1)t+b,x∈R}
x=t^2+(a+1)t+b
x' = 2t+(a+1) =0
t = -(a+1)/2
x'' = 2 >0 (min)
最小值 x = x(-(a+1)/2)
=(a+1)^2/4 - (a+1)^2/2 +b
= -(a+1)^2/4 +b
A = { x | x ≥-(a+1)^2/4 +b }
B={x|x=-t^2-(a-1)t-b,t∈R}
x= -t^2-(a-b)t-b
x' =-2t -(a-b)=0
t = -(a-b)/2
x''= -2 >0 (max)
最大值 x = x( -(a-1)/2)
= -(a-1)^2/4 +b
B={x|x≤-(a-1)^2/4 +b }
A∩B={x|-1≤x≤2}
=>
-(a+1)^2/4 +b =-1 (1)
-(a-1)^2/4 +b = 2 (2)
(2)-(1)
-(a-1)^2/4 +(a+1)^2/4 =3
a= 3
b=3
x=t^2+(a+1)t+b
x' = 2t+(a+1) =0
t = -(a+1)/2
x'' = 2 >0 (min)
最小值 x = x(-(a+1)/2)
=(a+1)^2/4 - (a+1)^2/2 +b
= -(a+1)^2/4 +b
A = { x | x ≥-(a+1)^2/4 +b }
B={x|x=-t^2-(a-1)t-b,t∈R}
x= -t^2-(a-b)t-b
x' =-2t -(a-b)=0
t = -(a-b)/2
x''= -2 >0 (max)
最大值 x = x( -(a-1)/2)
= -(a-1)^2/4 +b
B={x|x≤-(a-1)^2/4 +b }
A∩B={x|-1≤x≤2}
=>
-(a+1)^2/4 +b =-1 (1)
-(a-1)^2/4 +b = 2 (2)
(2)-(1)
-(a-1)^2/4 +(a+1)^2/4 =3
a= 3
b=3
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