Question

(-2^x+1)/(2^(x+1)+2)怎么化简到-（1/2）+1/(2^x+1)....急！！！

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Answer 1

(-2^x+1)/(2^(x+1)+2)
=（-2^x-1+2)/(2^(x+1)+2)
=-(2^x+1)/(2^(x+1)+2)+2/(2^(x+1)+2)
=-1/2+1/(2^x+1);

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Answer 2

(-2^x+1)/(2^(x+1)+2)
=(-2^x +1)/[2(2^x +1)]
=[-(2^x +1)+2]/[2(2^x +1)]
=[-(2^x +1)]/[2(2^x +1)]+ 2/[2(2^x +1)]
=-(1/2)+ 1/(2^x +1)

Answer 3

(-2^x+1)/[2^(x+1)+2]
=(-2^x-1+2)/[2*2^x+2]
=(-2^x-1)/[2(2^x+1)]+2/[2(2^x+1)]
=-(2^x+1)/[2(2^x+1)]+1/(2^x+1)
=-(1/2)+1/(2^x+1)