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2012-01-04 · 知道合伙人教育行家
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f(x) = cos2x / sin(π/4-x)
= (cos^2x-sin^2x) / (sinπ/4cosx-cosπ/4sinx)
= (cosx+sinx) / (cosx-sinx) / [√2/2(cosx-sinx)]
= √2(sinx+cosx)
= 2(sinxcosπ/4+cosxsinπ/4)
= 2sin(x+π/4)
定义域sin(π/4-x)≠0,x≠kπ+π/4
= (cos^2x-sin^2x) / (sinπ/4cosx-cosπ/4sinx)
= (cosx+sinx) / (cosx-sinx) / [√2/2(cosx-sinx)]
= √2(sinx+cosx)
= 2(sinxcosπ/4+cosxsinπ/4)
= 2sin(x+π/4)
定义域sin(π/4-x)≠0,x≠kπ+π/4
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2sin(x+π/4)
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