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f(x)=(2x+4-3)/(x+2)=2-3/(x+2)
可以由y=-3/x 对称中心(0,0)向右向上各平移2个单位后得到→对称中心(-2,2)
A.f(x)=(-4-2x+6)/(x+2)=-2+6/(x+2)→对称中心(-2,-2) ✘
B.f(x)=(2x+4+2)/(x+2)=2+2/(x+2)→对称中心(-2,2) ✔
C.f(x)=(-2+4-2x)/(2-x)=-2+2/(x-2)→对称中心(2,2) ✘
D.f(x)=(-4+2x+5)/(2-x)=-2-5/(x-2)→对称中心(2,-2) ✘
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虚线y=-3/x,蓝色:题干函数,紫色:B